Q29 · CSIR-NET Chemistry, June 2012
Paper: CSIR-NET June 2012 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Easy
The size of the d orbitals in $\mathrm{Si}, \mathrm{P}, \mathrm{S}$ and Cl follows the order.
(a)$\mathrm{Cl}>\mathrm{S}>\mathrm{P}>\mathrm{Si}$
(b)$\mathrm{Cl}>\mathrm{P}>\mathrm{S}>\mathrm{Si}$
(c)$\mathrm{P}>\mathrm{S}>\mathrm{Si}>\mathrm{Cl}$
(d)$\mathrm{Si}>\mathrm{P}>\mathrm{S}>\mathrm{Cl}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
The 3d orbitals contract as the nuclear charge rises across the period, so they are largest for Si and smallest for Cl: Si > P > S > Cl.
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