Q4 · CSIR-NET Chemistry, June 2012

Paper: CSIR-NET June 2012 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Dipole Moment Polarity · Marks: 2 · Difficulty: Hard

The decreasing order of dipole moment of molecules is

(a)$\mathrm{NF_3>NH_3>H_2O}$

(b)$\mathrm{NH_3>NF_3>H_3O}$

(c)$\mathrm{H_2O>NH_3>NF_3}$

(d)$\mathrm{H}_{2} \mathrm{O}>\mathrm{NF}_{3}>\mathrm{NH}_{3}$

Answer

Answer: C ✓ checked by 4AB · confidence high

The source book printed D; on checking, C is correct — see the explanation.

Book printed (d).

Explanation

Dipole moments: H₂O 1.85 D > NH₃ 1.47 D > NF₃ 0.23 D (the N–F bond dipoles oppose the lone-pair moment) — (c).

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