Q51 · CSIR-NET Chemistry, June 2012
Paper: CSIR-NET June 2012 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Marks: 2 · Difficulty: Easy
The final product of the reaction $[\mathrm{Mn}(\mathrm{CO})_{6}]^{+} + \mathrm{MeLi} \rightarrow$ is:
(a)$\left[\mathrm{Mn}(\mathrm{CO})_{6}\right]^{+} \mathrm{Me}^{-}$
(b)$\left[\mathrm{Mn}(\mathrm{CO})_{5} \mathrm{Me}\right]$
(c)$\left[\mathrm{Mn}(\mathrm{CO})_{6}\right]$
(d)$\left[(\mathrm{MeCO}) \mathrm{Mn}(\mathrm{CO})_{5}\right]$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
Carbanions attack the carbon of a coordinated CO in cationic carbonyls: [Mn(CO)₆]⁺ + MeLi → neutral acetyl complex [(MeCO)Mn(CO)₅].
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