Paper: CSIR-NET June 2012 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Marks: 2 · Difficulty: Medium
The quantitative determination of $\mathrm{N}_{2} \mathrm{H}_{4}$ with $\mathrm{KIO}_{3}$ proceeds in a mixture of $\mathrm{H}_{2} \mathrm{O} / \mathrm{CCl}_{4}$ as Follows
(c)Disappearance of the Yellow colour due to $\mathrm{Cl}_{2}$ in $\mathrm{CCl}_{4}$ layer.
(d)Displacement of the Red colour due to $\mathrm{I}_{2}$ in $\mathrm{CCl}_{4}$ layer
Answer
Answer: D ✓ checked by 4AB · confidence medium
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
Andrews' iodate titration: iodine formed at first colours the CCl₄ layer violet-red; the end point is when this I₂ colour disappears from the organic layer as all iodine becomes colourless ICl.