For a diatomic molecule AB, the energy for the rotational transition from J=0 to J=1 state is 3.9 cm⁻¹. The energy for the rotational transition from J=3 to J=4 state would be

Q74 · CSIR-NET Chemistry, June 2012

Paper: CSIR-NET June 2012 · Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Rotational · Marks: 2 · Difficulty: Medium

For a diatomic molecule AB, the energy for the rotational transition from $\mathrm{J}=0$ to $\mathrm{J}=1$ state is $3.9 \mathrm{cm}^{-1}$. The energy for the rotational transition from $\mathrm{J}=3$ to $\mathrm{J}=4$ state would be

(a)$3.9 \mathrm{cm}^{-1}$

(b)$7.8 \mathrm{cm}^{-1}$

(c)$11.7 \mathrm{cm}^{-1}$

(d)$15.6 \mathrm{cm}^{-1}$

Answer

Answer: D ✓ checked by 4AB · confidence high

Explanation

Rotational lines lie at 2B(J+1). J 0→1 = 2B = 3.9 cm⁻¹, so J 3→4 = 8B = 15.6 cm⁻¹ (d).

Study loop for Molecular Spectroscopy

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app