The following data were obtained from the vibrational fine structure in the vibronic spectrum of a diatomic molecule: ωe=512 cm⁻¹, ωe xe=8 cm⁻¹ where ωe is the energy associated with the natural frequency of vibration and xe is the anharmonicity constant. The dissociation energy (De) of the molecule is:

(c) 8192 cm⁻¹. Explanation: De = ωe²/(4ωeχe) = 512²/(4 × 8) = 8192 cm⁻¹.

Q76 · CSIR-NET Chemistry, June 2012

Paper: CSIR-NET June 2012 · Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Vibrational · Marks: 2 · Difficulty: Medium

The following data were obtained from the vibrational fine structure in the vibronic spectrum of a diatomic molecule: $\omega_{\mathrm{e}}=512 \mathrm{cm}^{-1}, \omega_{\mathrm{e}} \mathrm{x}_{\mathrm{e}}=8 \mathrm{cm}^{-1}$ where $\omega_{\mathrm{e}}$ is the energy associated with the natural frequency of vibration and xe is the anharmonicity constant. The dissociation energy (De) of the molecule is:

(a)$4096 \mathrm{cm}^{-1}$

(b)$6144 \mathrm{cm}^{-1}$

(c)$8192 \mathrm{cm}^{-1}$

(d)$16384 \mathrm{cm}^{-1}$

Answer

Answer: C ✓ checked by 4AB · confidence high

Explanation

D_e = ω_e²/(4ω_eχ_e) = 512²/(4 × 8) = 8192 cm⁻¹.

Study loop for Molecular Spectroscopy

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app