The adsorption of a gas is described by the Langmuir isotherm with the equilibrium constant K =0.9 kPa⁻¹ at 25°C. The pressure (in kPa) at which the fractional surface coverage is 0.95, is

(b) 21.1. Explanation: θ/(1 − θ) = Kp ⇒ 0.95/0.05 = 19 = 0.9p ⇒ p = 21.1 kPa.

Q96 · CSIR-NET Chemistry, June 2012

Paper: CSIR-NET June 2012 · Subject: Physical Chemistry · Chapter: Surface Chemistry · Topic: Adsorption Isotherms · Marks: 2 · Difficulty: Medium

The adsorption of a gas is described by the Langmuir isotherm with the equilibrium constant K $=0.9\,\mathrm{kPa^{-1}}$ at 25°C. The pressure (in kPa) at which the fractional surface coverage is 0.95, is

(a)1/11.1

(b)21.1

(c)11.1

(d)42.2

Answer

Answer: B ✓ checked by 4AB · confidence high

Explanation

θ/(1 − θ) = Kp ⇒ 0.95/0.05 = 19 = 0.9p ⇒ p = 21.1 kPa.

Study loop for Surface Chemistry

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app