Q59 · CSIR-NET Chemistry, June 2013

Paper: CSIR-NET June 2013 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Marks: 2 · Difficulty: Easy

The oxidation state of molybdenum in $\left[\left(\eta^{7} \text {-tropylium }\right) \mathrm{Mo}(\mathrm{CO})_{3}\right]^{+}$is:
(a)+2
(b)+1
(c)0
(d)-1
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
Counting the tropylium ring as the aromatic C₇H₇⁺ cation (6 π electrons, L₃) and CO as neutral, the metal is Mo(0).

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