Q61 · CSIR-NET Chemistry, June 2013
Paper: CSIR-NET June 2013 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Marks: 2 · Difficulty: Medium
The orders of reactivity of ligands, NMe3 PMe3, and CO with complexes MeTiCl, and $(\mathrm{CO})_{5} \mathrm{Mo}$ (thf) are
(a)$\mathrm{CO}>\mathrm{PMe}_{3}>\mathrm{NMe}_{3}$ and $\mathrm{CO}>\mathrm{NMe}_{3}>\mathrm{PMe}_{3}$
(b)$\mathrm{PMe}_{3}>\mathrm{CO}>\mathrm{NMe}_{3}$ and $\mathrm{NMe}_{3}>\mathrm{CO}>\mathrm{PMe}_{3}$
(c)$\mathrm{NMe}_{3}>\mathrm{PMe}_{3}>\mathrm{CO}$ and $\mathrm{CO}>\mathrm{PMe}_{3}>\mathrm{NMe}_{3}$
(d)$\mathrm{NMe}_{3}>\mathrm{CO}>\mathrm{PMe}_{3}$ and $\mathrm{PMe}_{3}>\mathrm{NMe}_{3}>\mathrm{CO}$
Answer
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Explanation
Hard Ti(IV): NMe₃ > PMe₃ > CO; soft Mo(0): CO > PMe₃ > NMe₃ (c).
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