Paper: CSIR-NET June 2013 · Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Molecular Spectroscopy – General · Marks: 2 · Difficulty: Medium
In NMR spectroscopy, the product of the nuclear 'g' factor $\left(\mathrm{g}_{\mathrm{N}}\right)$, the nuclear magneton $\left(\beta_{\mathrm{N}}\right)$ and the magnetic field strength $\left(\mathrm{B}_{0}\right)$ gives the
(a)energy of transition from $\alpha$ to $\beta$ state
(b)chemical shift
(c)spin-spin coupling constant
(d)gyromagnetic ratio
Answer
Answer: A ✓ checked by 4AB · confidence high
The source book printed B; on checking, A is correct — see the explanation.
Explanation
ΔE = g_N μ_N B₀ is the energy separation between the α and β nuclear spin states — the transition energy (hν).