4AB › Chemistry PYQ › CSIR-NET › June 2014 › Q27Q27 · CSIR-NET Chemistry, June 2014 Paper: CSIR-NET June 2014 · Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Electron Transfer Redox · Marks: 2 · Difficulty: Medium
In its electronic spectrum, $\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ exihibits two absorption bands, one at 17,800 ($v_1$) and the second at 25, 700 ($v_2$) cm. The correct assignment of these bands, respectively, is
(a) $v_1 = {}^3T_{1g}(F) \rightarrow {}^3T_{2g}(F)$, $V_2 = {}^3T_{1g}(F) \rightarrow {}^3T_{1g}(P)$
(b) $v_1 = {}^3T_{1g}(F) \rightarrow {}^3T_{1g}(P)$, $V_2 = {}^3T_{1g}(F) \rightarrow {}^3T_{2g}(P)$
(c) $v_1 = {}^3A_{2g} \rightarrow {}^3T_{1g}(F)$, $V_2 = {}^3A_{2g} \rightarrow {}^3T_{2g}(F)$
(d) $v_1 = {}^3A_{2g} \rightarrow {}^3T_{2g}(F)$, $V_2 = {}^3A_{2g} \rightarrow {}^3T_{1g}($ (F)
Answer Answer: A ✓ checked by 4AB · confidence high
Explanation V(III) d² (³T₁g ground): ν₁ = ³T₁g(F) → ³T₂g (17,800) and ν₂ = ³T₁g(F) → ³T₁g(P) (25,700 cm⁻¹); the ³A₂g band is usually hidden.
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