Q83 · CSIR-NET Chemistry, June 2014
Paper: CSIR-NET June 2014 · Subject: Physical Chemistry · Chapter: Quantum Chemistry · Topic: Angular Momentum · Marks: 2 · Difficulty: Medium
The spatial part of the wave function of the atom in its ground state is $1 \mathrm{s}(1) 1 \mathrm{s}(2)$. The spin part would be
(a)$\alpha(1) \alpha(2)$
(b)$\beta(1) \beta(2)$
(c)$\frac{1}{\sqrt{2}}[\alpha(1) \beta(2)+\beta(1) \alpha(2)]$
(d)$\frac{1}{\sqrt{2}}[\alpha(1) \beta(2)-\beta(1) \alpha(2)]$
Answer
Answer: C ✓ checked by 4AB · confidence medium
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
The symmetric space part 1s(1)1s(2) must be combined with the antisymmetric spin singlet (1/√2)[α(1)β(2) − β(1)α(2)].
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