Q98 · CSIR-NET Chemistry, June 2014

Paper: CSIR-NET June 2014 · Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Equilibrium · Marks: 2 · Difficulty: Medium

The number of configurations in the most probable state, according to Boltzmann formula, is

(a)$\mathrm{e}^{\frac{\mathrm{S}}{\mathrm{k}_{\mathrm{B}}}}$

(b)$\mathrm{e}^{\frac{-\mathrm{S}}{\mathrm{k}_{\mathrm{B}}}}$

(c)$\mathrm{e}^{\frac{-\mathrm{E}}{\mathrm{k}_{\mathrm{B}} \mathrm{T}}}$

(d)$\mathrm{e}^{\frac{-\Delta \mathrm{G}}{\mathrm{k}_{\mathrm{B}} \mathrm{T}}}$

Answer

Answer: A ✓ checked by 4AB · confidence high

The source book printed B; on checking, A is correct — see the explanation.

Explanation

Boltzmann: S = k ln W, so W = e^(S/k) (a).

Study loop for Statistical Thermodynamics