The lowest energy-state of an atom with electronic configuration ns¹ np¹ has the term symbol

Q24 · CSIR-NET Chemistry, June 2015

Paper: CSIR-NET June 2015 · Subject: Physical Chemistry · Chapter: Atomic and Molecular Term Symbol · Topic: Term Symbols Atoms · Marks: 2 · Difficulty: Medium

The lowest energy-state of an atom with electronic configuration $\mathrm{ns}^{1} \mathrm{np}^{1}$ has the term symbol

(a)${ }^{3} \mathrm{P}_{1}$

(b)${ }^{1} \mathrm{P}_{1}$

(c)${ }^{3} \mathrm{P}_{2}$

(d)${ }^{3} \mathrm{P}_{0}$

Answer

Answer: D ✓ checked by 4AB · confidence high

Explanation

ns¹np¹ gives ¹P and ³P. Hund: the triplet lies lowest, and for a less-than-half-filled shell the smallest J is lowest, so ³P₀.

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