Q47 · CSIR-NET Chemistry, June 2015
Paper: CSIR-NET June 2015 · Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Electron Transfer Redox · Marks: 2 · Difficulty: Medium
Match the complexes given in column I with the electronic transitions (mainly responsible for their colours) listed in column II | Column-I | Column-II |
|---|
| (I) Fe(II)-protoporphyrin IX | (A) $\pi \rightarrow \pi^{*}$ |
| (II) $[\mathrm{Mn}(\mathrm{H}_2\mathrm{O})_6]\mathrm{Cl}_2$ | (B) spin allowed d-d |
| (III) $[\mathrm{Co}(\mathrm{H}_2\mathrm{O})_6]\mathrm{Cl}_2$ | (C) spin forbidden $d \rightarrow d$ |
| (D) $M \rightarrow L$ charge transfer |
The correct answer is: (a)I-A, II-C and III-B
(b)I-D, II-B and III-C
(c)1-A, II-C and III-D
(d)I-A, II-B and III-C
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
The Fe-porphyrin colour comes from π→π* bands. [Mn(H₂O)₆]²⁺ (d⁵) shows only spin-forbidden d–d bands. [Co(H₂O)₆]²⁺ shows spin-allowed d–d bands. I-A, II-C, III-B (a).
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