Consider the following statements for $\left(\mathrm{NH}_{4}\right)_{2}\left[\mathrm{Ce}\left(\mathrm{NO}_{3}\right)_{6}\right](\mathrm{Z})$
(a)Coordination number of Ce is 12
(b)Z is paramagnetic
(c)Z is an oxidising agent
(d)Reaction of $\mathrm{Ph}_{3} \mathrm{PO}$ with Z gives a complex having coordination number 10 for Ce .
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
(NH₄)₂[Ce(NO₃)₆] has six bidentate nitrates, so Ce is CN 12. Ce(IV) is f⁰ (diamagnetic) and a strong oxidant. Ph₃PO forms [Ce(NO₃)₄(OPPh₃)₂], CN 10. A, C and D (d).