Total number of vertices in metal clusters [Ru₆(C)(CO)₁₇] [Os₅(C)(CO)₁₅] and [Ru₅(C)(CO)₁₆] are 6,5 and 5, respectively. The predicted structures of these complexes, respectively are

Q68 · CSIR-NET Chemistry, June 2015

Paper: CSIR-NET June 2015 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Marks: 2 · Difficulty: Medium

Total number of vertices in metal clusters $\left[\mathrm{Ru}_{6}(\mathrm{C})(\mathrm{CO})_{17}\right]\left[\mathrm{Os}_{5}(\mathrm{C})(\mathrm{CO})_{15}\right]$ and $\left[\mathrm{Ru}_{5}(\mathrm{C})(\mathrm{CO})_{16}\right]$ are 6,5 and 5, respectively. The predicted structures of these complexes, respectively are

(a)closo, nido and nido

(b)closo, nido and arachno

(c)arachno, closo and nido

(d)arachno, nido and closo

Answer

Answer: B ✓ checked by 4AB · confidence high

Explanation

Ru₆C(CO)₁₇: 48 + 4 + 34 = 86 = 14n + 2 → closo; Os₅C(CO)₁₅: 40 + 4 + 30 = 74 = 14n + 4 → nido; Ru₅C(CO)₁₆: 76 = 14n + 6 → arachno.

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