Paper: CSIR-NET June 2015 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Arrhenius Activation · Marks: 2 · Difficulty: Medium
The temperature-dependence of a reaction is given by $\mathrm{k}=\mathrm{AT}^{2} \exp \left(-\mathrm{E}_{0} / \mathrm{RT}\right)$ The activation energy $\mathrm{E}_{\mathrm{a}}$ of the reaction is given by:
(a)$\mathrm{E}_{0}+\frac{1}{2} \mathrm{RT}$
(b)$\mathrm{E}_{0}$
(c)$\mathrm{E}_{0}+2 \mathrm{RT}$
(d)$2 \mathrm{E}_{0}+\mathrm{RT}$
Answer
Answer: C ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
Ea = RT² d ln k/dT = RT²(2/T + E₀/RT²) = E₀ + 2RT.