Q84 · CSIR-NET Chemistry, June 2015

Paper: CSIR-NET June 2015 · Subject: Physical Chemistry · Chapter: Data Analysis · Topic: Error Propagation · Marks: 2 · Difficulty: Easy

If $\mathrm{y}_{2}=4 \mathrm{x}$ and $0.1 \%$ error is incurred for x , the percentage error involved in y will be

(a)0.4

(b)0.025

(c)0.1

(d)0.05

Answer

Answer: C ✓ checked by 4AB · confidence high

The source book printed D; on checking, C is correct — see the explanation.

Explanation

Values 1.71, 1.77, 1.79, 1.73 (×10⁻⁵): mean 1.75; deviations ±0.04, ±0.02; s = √[(16 + 4 + 16 + 4)×10⁻⁴/3] = 0.037 ×10⁻⁵ — in the 0.03–0.039 range.

Study loop for Data Analysis