Q13 · CSIR-NET Chemistry, June 2016

Paper: CSIR-NET June 2016 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Marks: 2 · Difficulty: Medium

Experimentally determined rate law for the chemical reaction, $2\mathrm{NO_2F} \rightarrow 2\mathrm{NO_2}+\mathrm{F_2}$ is $R=k[\mathrm{NO_2F}]$ The rate determining step consistent with the rate law is
(a)$2\mathrm{NO_2F} \rightarrow 2\mathrm{NO_2}+\mathrm{F_2}$
(b)$\mathrm{NO_2F}+\mathrm{F} \rightarrow \mathrm{NO_2}+\mathrm{F_2}$
(c)$\mathrm{NO_2F} \rightarrow \mathrm{NO_2}+\mathrm{F}$
(d)$\mathrm{NO_2}+\mathrm{F} \rightarrow \mathrm{NO_2F}$
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
A unimolecular slow step NO₂F → NO₂ + F, followed by fast NO₂F + F → NO₂ + F₂, gives R = k[NO₂F] (c).

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