Q15 · CSIR-NET Chemistry, June 2016
Paper: CSIR-NET June 2016 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Medium
In a potentiometric titration, the end point is characterised by
(a)$\frac{d E}{d V}=0 ; \frac{d^{2} E}{d^{2} V}=0$
(b)$\frac{d E}{d V} \neq 0 ; \frac{d^{2} E}{d^{2} V}=0$
(c)$\frac{d E}{d V}=0 ; \frac{d^{2} E}{d^{2} V} \neq 0$
(d)$\frac{d E}{d V} \neq 0 ; \frac{d^{2} E}{d^{2} V} \neq 0$
Answer
Answer: B ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
At the end point of a potentiometric titration E rises most steeply: dE/dV is maximum (not zero) and d²E/dV² = 0 (the inflection point) (b).
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