Paper: CSIR-NET June 2016 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Thermodynamics – General · Marks: 2 · Difficulty: Medium
Under review — part of this question (a structure or an option) is not clear in the source scan. 4AB is checking it against the original book; the answer shown may change.
If $U$ is a function of $V$ and $T,\left(\frac{\partial U}{\partial T}\right)_{P}$ is equal to $(\pi$ and $\alpha$ are the internal pressure and the coefficient of thermal expansion, respectively)
(a)$\mathrm{C_P}$
(b)$\mathrm{C}_{\mathrm{V}}$
(c)$\mathrm{C_P} - \pi\alpha V$
(d)$\mathrm{C_P} + \pi\alpha V$
Answer
Under review — not yet confirmed.
Answer: D
Explanation
dU = C_V dT + π_T dV, so (∂U/∂T)_P = C_V + π_T (∂V/∂T)_P = C_V + π_T αV. Option (d) as originally set reads C_V + παV (the scan shows C_P by an OCR slip).