Q67 · CSIR-NET Chemistry, June 2016
Paper: CSIR-NET June 2016 · Subject: Physical Chemistry · Chapter: Group Theory · Topic: Reducible Representations · Marks: 2 · Difficulty: Hard
The character table of $\mathrm{C}_{3 \mathrm{v}}$ point group is provided below, along with an additional reducible representation, $\Gamma$ | E | $2 \mathrm{C}_{3}$ | $3 \sigma_{\mathrm{v}}$ |
|---|
| $\mathrm{A}_{1}$ | 1 | 1 | 1 |
| $\mathrm{A}_{2}$ | 1 | 1 | -1 |
| E | 2 | -1 | 0 |
| Г | 6 | 0 | 2 |
$\Gamma$ is given by (a)$\mathrm{A}_{1}+\mathrm{A}_{2}+\mathrm{E}$
(b)$2 \mathrm{A}_{1}+2 \mathrm{E}$
(c)$2 \mathrm{A}_{2}+2 \mathrm{E}$
(d)$2 \mathrm{A}_{1}+2 \mathrm{A}_{2}+\mathrm{E}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Reduce Γ = (6, 0, 2): n(A₁) = (6 + 0 + 6)/6 = 2, n(A₂) = (6 + 0 − 6)/6 = 0, n(E) = (12 + 0 + 0)/6 = 2. So Γ = 2A₁ + 2E (b).
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