Q80 · CSIR-NET Chemistry, June 2016
Paper: CSIR-NET June 2016 · Subject: Physical Chemistry · Chapter: Quantum Chemistry · Topic: Hydrogen Atom · Marks: 2 · Difficulty: Easy
The correct normalized wave function for one of the $\mathrm{sp}^{2}$ hybrid orbitals is
(a)$\frac{1}{3} \psi_{2s}-\frac{1}{3} \psi_{2px}+\frac{1}{3} \psi_{2py}$
(b)$\frac{1}{\sqrt{3}} \psi_{2s}-\frac{2}{\sqrt{3}} \psi_{2px}+\frac{1}{\sqrt{6}} \psi_{2py}$
(c)$\frac{1}{\sqrt{3}} \psi_{2s}-\frac{1}{\sqrt{2}} \psi_{2px}+\frac{1}{\sqrt{6}} \psi_{2py}$
(d)$\frac{1}{\sqrt{3}} \psi_{2s}-\frac{1}{2\sqrt{2}} \psi_{2px}+\frac{1}{\sqrt{6}} \psi_{2py}$
Answer
Answer: C ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
For an sp² hybrid the coefficients squared must sum to 1 with s = 1/3: 1/3 + 1/2 + 1/6 = 1 (c).
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