Reaction of $\mathrm{Na}\left[\mathrm{Mn}(\mathrm{CO})_{5}\right]$ with $\mathrm{H}_{3} \mathrm{C}=\mathrm{CHCH}_{2} \mathrm{Cl}$ gives A along with NaCl . Photolysis of compound A results in compound B together with elimination of CO . The correct structural formulations of compounds A and B are respectively,
(a)
(b)B B
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
[Mn(CO)₅]⁻ displaces Cl⁻ to give σ-allyl (η¹-CH₂CH=CH₂)Mn(CO)₅ (A). Photolysis expels CO and the allyl becomes η³: (η³-C₃H₅)Mn(CO)₄ (B) (a).