Q57 · CSIR-NET Chemistry, June 2017

Paper: CSIR-NET June 2017 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Medium

The electrochemical cell potential (E), after the reactants and products reach equilibrium, is $\left(\mathrm{E}^{0}\right.$ is the standard cell potential and n is the number of electrons involved)
(a)$\mathrm{E}=\mathrm{E}^{\circ}+\frac{\mathrm{nF}}{\mathrm{RT}}$
(b)$\mathrm{E}=\mathrm{E}^{\circ}-\frac{\mathrm{nF}}{\mathrm{RT}}$
(c)$\mathrm{E}=\mathrm{E}^{\circ}$
(d)$\mathrm{E}=0$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
At equilibrium the cell can do no more work: E = 0 (and E° = (RT/nF) ln K).

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