Q23 · CSIR-NET Chemistry, June 2018

Paper: CSIR-NET June 2018 · Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acids & Bases – General · Marks: 2 · Difficulty: Medium

The transformation are given in Column 1 and reagent in Column II. Match the items of Column I with those of Column II
Column IColumnII
(a) $[\mathrm{MnO_4}]^{-} \rightarrow [\mathrm{MnO_4}]^{2-}$(i) $\mathrm{H_2SO_4}$
(b) $\mathrm{Me_3CH} \rightarrow [\mathrm{Me_3C}]^{+}$(ii) Na in liquid $\mathrm{NH_3}$
(c) $\mathrm{Ag+Au} \rightarrow [\mathrm{AuF_4}]$(iii) $[\mathrm{H_2SO_4F}]^{+}$ (super acid)
(d) $\mathrm{H_3PO_4} \rightarrow [\mathrm{P(OH)_4}]^{+}$(iv) Liquid $\mathrm{BrF_3}$
(a)(a)-(i); (b)-(ii); (c)-(iii); (d)-(iv)
(b)(a)-(ii); (b)-(iii); (c)-(iv); (d)-(i)
(c)(a)-(iii); (b)-(ii); (c)-(i); (d)-(iv)
(d)(a)-(iii); (b)-(i); (c)-(iv); (d)-(ii)
Answer
Answer: B ✓ checked by 4AB · confidence medium

The source book printed C; on checking, B is correct — see the explanation.

Explanation
(a) MnO₄⁻ → MnO₄²⁻ is a one-electron reduction (Na/NH₃). (b) The superacid abstracts hydride from Me₃CH, giving the t-Bu⁺ cation. (c) BrF₃ fluorinates Ag + Au to Ag[AuF₄]. (d) H₂SO₄ protonates H₃PO₄ to P(OH)₄⁺ (b).

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