The lowest energy state of a 1s¹2s¹ electronic configuration, according to hund's rule, is

Q35 · CSIR-NET Chemistry, June 2018

Paper: CSIR-NET June 2018 · Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Electron Transfer Redox · Marks: 2 · Difficulty: Medium

The lowest energy state of a $1s^{1}2s^{1}$ electronic configuration, according to hund's rule, is

(a)$^{3}S_{0}$

(b)$^{1}S_{0}$

(c)$^{3}S_{1}$

(d)$^{1}S_{1}$

Answer

Answer: C ✓ checked by 4AB · confidence high

Explanation

1s¹2s¹: the triplet lies lowest (Hund), L = 0, J = 1 → ³S₁.

Study loop for Coordination Chemistry