Paper: CSIR-NET June 2018 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Complex Reactions · Marks: 2 · Difficulty: Medium
Difference between-activation energies of the reverse and forward steps of a reversible reaction is 9.212 RT . If the pre-exponential factor of the forward reaction is double that of the reverse reaction at the same temperature, the equilibrium constant for the reaction at that temperature will be $(\ln 10=2.303)$
(a)$1 \times 10^{4}$
(b)$2 \times 10^{4}$
(c)$1 \times 10^{-4}$
(d)$2 \times 10^{-4}$
Answer
Answer: B ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.