Q69 · CSIR-NET Chemistry, June 2018

Paper: CSIR-NET June 2018 · Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Molecular Spectroscopy – General · Marks: 2 · Difficulty: Medium

Assuming harmonic approximation, the energy change for the reaction $\mathrm{HCl}+\mathrm{D}_{2} \rightarrow \mathrm{DCl}+\mathrm{HD}$ in $\mathrm{cm}^{-1}$ is (the vibrational frequency data in $\mathrm{cm}^{-1}$ is given in the table below),
HCl$\mathrm{D}_{2}$DClHD
2885299019903627
(a)-258
(b)+258
(c)-129
(d)+129
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
Only zero-point energies change: ΔE = ½[ν(DCl) + ν(HD) − ν(HCl) − ν(D₂)] = ½(1990 + 3627 − 2885 − 2990) = −129 cm⁻¹.

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