Q78 · CSIR NET Chemistry, June 2018
Paper: CSIR NET June 2018 · Subject: Physical Chemistry · Chapter: Surface Chemistry · Topic: Surface Chemistry – General · Marks: 2 · Difficulty: Medium
In fission of ${ }^{\mathrm{235}} \mathrm{U}$ atom the energy released is 200 MeV . In one day fission of $1 \mathrm{kg}^{235} \mathrm{U}$ will give power (in MW) approximately
(a)550
(b)650
(c)950
(d)1250
Answer
Answer: C ✓ checked by 4AB · confidence high
The source book printed D; on checking, C is correct — see the explanation.
Printed D; 8.2×10¹³ J / 86400 s = 950 MW.
Explanation
N = (1000/235) × 6.022×10²³ = 2.56×10²⁴ atoms; E = 2.56×10²⁴ × 200×10⁶ × 1.6×10⁻¹⁹ J = 8.2×10¹³ J. Over one day (86400 s): P = 9.5×10⁸ W ≈ 950 MW.
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