If the overpotential of an electrolysis process is increased from 0.5 V to 0.6 V , then the ratio of current densities $\left(\ln \frac{\mathrm{J}_{0.6}}{\mathrm{J}_{0.5}}\right)$ of the electrolysis will be equal to (given transfer coefficient $=0.5$ )
(a)$0.5 \frac{F}{R T}$
(b)$0.05 \frac{F}{R T}$
(c)$0.1 \frac{F}{R T}$
(d)$0.01 \dfrac{F}{RT}$
Answer
Answer: B ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.