The cations formed upon dissolving SnF₄ and AuF₃ in liquid BrF₃ separately, respectively are

Q18 · CSIR-NET Chemistry, June 2019

Paper: CSIR-NET June 2019 · Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acids & Bases – General · Marks: 2 · Difficulty: Medium

The cations formed upon dissolving $\mathrm{SnF}_{4}$ and $\mathrm{AuF}_{3}$ in liquid $\mathrm{BrF}_{3}$ separately, respectively are

(a)$\mathrm{SnF}_{3}^{+}$and $\mathrm{BrF}_{2}^{+}$

(b)$\mathrm{BrF}_{2}^{+}$and $\mathrm{AuF}_{2}^{+}$

(c)$\mathrm{BrF}_{2}^{+}$only

(d)$\mathrm{SnF}_{3}^{+}$and $\mathrm{AuF}_{2}^{+}$

Answer

Answer: C ✓ checked by 4AB · confidence high

Explanation

SnF₄ and AuF₃ are fluoride acceptors, so only BrF₂⁺ cations form (c).

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