If the over potential of an electrolysis process is increased from 0.5V to 0.6V, then the ratio of current densities (ln J0.6/J0.5) of the electrolysis will be equal to (given transfer coefficient =0.5)

(b) 0.05 F/RT. Explanation: Tafel: ln(J₀.₆/J₀.₅) = αFΔη/RT = 0.5 × 0.1 F/RT = 0.05F/RT (b).

Q67 · CSIR-NET Chemistry, June 2019

Paper: CSIR-NET June 2019 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Medium

If the over potential of an electrolysis process is increased from 0.5V to 0.6V, then the ratio of current densities $\left(\ln \frac{\mathrm{J}_{0.6}}{\mathrm{J}_{0.5}}\right)$ of the electrolysis will be equal to (given transfer coefficient $=0.5$ )

(a)$0.5 \frac{\mathrm{F}}{\mathrm{RT}}$

(b)$0.05 \frac{\mathrm{F}}{\mathrm{RT}}$

(c)$0.1 \frac{\mathrm{F}}{\mathrm{RT}}$

(d)$0.01 \frac{\mathrm{F}}{\mathrm{RT}}$

Answer

Answer: B ✓ checked by 4AB · confidence high

Explanation

Tafel: ln(J₀.₆/J₀.₅) = αFΔη/RT = 0.5 × 0.1 F/RT = 0.05F/RT (b).

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