The Berge-Sponer plot between Δ Gv+1/2= (εv+1-εv) and v+1 for CO in a straight line with slope of -14 cm⁻¹ and intercept of 2170 cm⁻¹. The approximate value of dissociation energy of CO (in c m⁻¹) is (Assume CO as an Anharmonic oscillator with energy expression. εv= (v+1/2) ω- (v+1/2)² xe ω; D=(ω)/4 xe

Q71 · CSIR-NET Chemistry, June 2019

Paper: CSIR-NET June 2019 · Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Vibrational · Marks: 2 · Difficulty: Medium

The Berge-Sponer plot between $\Delta \mathrm{G}_{\mathrm{v}+\frac{1}{2}}=\left(\varepsilon_{\mathrm{v}+1}-\varepsilon_{\mathrm{v}}\right)$ and $v+1$ for CO in a straight line with slope of $-14 \mathrm{cm}^{-1}$ and intercept of $2170 \mathrm{cm}^{-1}$. The approximate value of dissociation energy of CO (in $c m^{-1}$ ) is (Assume CO as an Anharmonic oscillator with energy expression.

\[ \varepsilon_{v}=\left(v+\frac{1}{2}\right) \omega-\left(v+\frac{1}{2}\right)^{2} x_{e} \omega ; D=\frac{\omega}{4 x_{e}} \]

(a)42044

(b)84088

(c)168175

(d)336350

Answer

Answer: B ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Printed C; 2170²/(4 × 14) = 84,088.

Explanation

With the expression given in the question, D_e = ω_e²/(4ω_eχ_e), and ω_e = 2170, ω_eχ_e = 14 cm⁻¹: D_e = 2170²/(4 × 14) = 4,708,900/56 = 84,088 cm⁻¹.

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