For a linear molecule the mean energies for translation, rotation $\left(\mathrm{T} \gg \theta_{\mathrm{r}}\right)$ and vibration $\left(\mathrm{T} \gg \theta_{\mathrm{v}}\right)$ follow ratio:
(a)$1: \frac{3}{2}: 1$
(b)$\frac{3}{2}: 1: 1$
(c)$1: \frac{1}{2}: 1$
(d)$\frac{1}{2}: 1: 1$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Per molecule, translation gives 3/2 kT, rotation of a linear molecule kT, and each vibration kT. The ratio is 3/2 : 1 : 1 (b).