Q1 · CSIR-NET Chemistry, June 2021
Paper: CSIR-NET June 2021 · Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acids & Bases – General · Marks: 2 · Difficulty: Medium
Identify the correct statement for the two reactions given below \[ \begin{array}{l} \mathrm{Xe}+\mathrm{PtF}_{6} \xrightarrow{\mathrm{SF}_{6}} [\mathrm{Xe}]^{+}[\mathrm{PtF}_{6}]^{-} \\ \mathrm{XeF}_{4}+\mathrm{Me}_{4}\mathrm{NF} \rightarrow [\mathrm{Me}_{4}\mathrm{N}]^{+}[\mathrm{XeF}_{5}]^{-} \end{array} \]
(a)Xe and $\mathrm{XeF}_{4}$ both act as acids.
(b)Xe and $\mathrm{XeF}_{4}$ both act as bases.
(c)Xe acts as an acid and $\mathrm{XeF}_{4}$ acts as a base.
(d)Xe acts as a base and $\mathrm{XeF}_{4}$ acts as an acid.
Answer
Answer: D ✓ checked by 4AB · confidence medium
The source book printed C; on checking, D is correct — see the explanation.
Explanation
Xe + PtF₆ → Xe⁺[PtF₆]⁻: xenon donates an electron (reductant/base). XeF₄ + Me₄NF → [Me₄N]⁺[XeF₅]⁻: XeF₄ accepts F⁻ (Lewis acid).
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