Q105 · CSIR NET Chemistry, December 2014
Paper: CSIR NET December 2014 · Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Equilibrium · Marks: 2 · Difficulty: Medium
The probability of finding the harmonic oscillator in the energy level $n=1$ is (neglect zero point energy and assume $h v=\mathrm{k}_{\mathrm{B}} \mathrm{T}$ )
(a)e
(b)$\mathrm{e}^{2}$
(c)$1-\mathrm{e}^{2}$
(d)$\mathrm{e}^{-2}(\mathrm{e}-1)$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
P(1) = e⁻¹(1 − e⁻¹) = (e − 1)/e² (d).
Study loop for Statistical Thermodynamics