Q67 · CSIR NET Chemistry, December 2015
Paper: CSIR NET December 2015 · Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Marks: 2 · Difficulty: Medium
Consider the following reaction :
\[ \mathrm{N_3P_3Cl_6} + 6\,\mathrm{HNMe_2} \rightarrow \mathrm{N_3P_3Cl_3(NMe_2)_3} + 3\,\mathrm{Me_2NH.HCl} \quad\text{(A)} \]
The number of possible isomers for [A] is(a)4
(b)3
(c)2
(d)5
Answer
Answer: A ✓ checked by 4AB · confidence high
The source book printed B; on checking, A is correct — see the explanation.
Explanation
N₃P₃Cl₃(NMe₂)₃: one geminal and two non-geminal (cis and trans) isomers — three (b).
Study loop for Main Group Elements