Q77 · CSIR NET Chemistry, December 2017
Paper: CSIR NET December 2017 · Subject: Physical Chemistry · Chapter: Solid State Chemistry · Topic: Crystal Systems Lattices · Marks: 2 · Difficulty: Medium
The separation of the (123) planes of an orthorhombic unit cell is 3.12 nm . The separation of (246) and (369) planes are, respectively,
(a)1.56 nm and 1.04 nm
(b)1.04 nm and 1.56 nm
(c)3.12 m and 1.50nm
(d)1.04 nm and 3.12 nm
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
(246) = 2 × (123) ⇒ d = 3.12/2 = 1.56 nm; (369) = 3 × (123) ⇒ d = 3.12/3 = 1.04 nm.
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