Q1 · CSIR NET Chemistry, June 2011
Paper: CSIR NET June 2011 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Easy
The highest occupied MO in $\mathrm{N_2}$ and $\mathrm{O_2^{+}}$ respectively are (take x-axis as internuclear axis)
(a)$\sigma_{2px}$ , $\pi^{*}_{2py}$
(b)$\pi_{2p_y},\ \pi_{2p_z}$
(c)$\sigma^*_{2p_x},\ \sigma_{2p_x}$
(d)$\pi^*_{2p_y},\ \pi^*_{2p_z}$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
With x as the bond axis, the HOMO of N₂ is σ2pₓ (s–p mixing raises it above π); O₂⁺ has one electron in π*2p — $\sigma_{2p_x}$ and $\pi^{*}_{2p_y}$ (a).
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