Q59 · CSIR NET Chemistry, June 2017
Paper: CSIR NET June 2017 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Medium
The standard cell potential for the reaction $\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(\mathrm{aq}) \Leftrightarrow \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})$ is +1.10 V . The Gibbs free energy change during the reaction is $\left(\mathrm{F}=96500\right.$ coulomb $\left.\mathrm{mol}^{-1}\right)$
(a)$-21.2 \mathrm{kJ} \mathrm{mol}^{-1}$
(b)$+212 \mathrm{kJ} \mathrm{mol}^{-1}$
(c)$-212 \mathrm{kJ} \mathrm{mol}^{-1}$
(d)$-212 \mathrm{J} \mathrm{mol}^{-1}$
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
ΔG° = −nFE° = −2 × 96500 × 1.10 = −212,300 J = −212 kJ mol⁻¹.
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