Q67 · CSIR NET Chemistry, June 2019
Paper: CSIR NET June 2019 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Medium
If the over potential of an electrolysis process is increased from 0.5V to 0.6V, then the ratio of current densities $\left(\ln \frac{\mathrm{J}_{0.6}}{\mathrm{J}_{0.5}}\right)$ of the electrolysis will be equal to (given transfer coefficient $=0.5$ )
(a)$0.5 \frac{\mathrm{F}}{\mathrm{RT}}$
(b)$0.05 \frac{\mathrm{F}}{\mathrm{RT}}$
(c)$0.1 \frac{\mathrm{F}}{\mathrm{RT}}$
(d)$0.01 \frac{\mathrm{F}}{\mathrm{RT}}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Tafel: ln(J₀.₆/J₀.₅) = αFΔη/RT = 0.5 × 0.1 F/RT = 0.05F/RT (b).
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