Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:
What could be the maximum value of Q in the following equation? 5P9 + 3R7 + 2Q8 = 1114
Answer
Answer (as printed):
Explanation
We may analyse the given equation as shown: 2 Q8 Clearly, 2 + P + R + Q = 11. 1 1 1 4 So, the maximum value of Q can be (11 – 2), i.e. 9 (when P = 0, R = 0).
Explanation as extracted from the printed page; notation may be imperfect.