ABC26GN0015 · Number System

Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:

Given that $1^{2}+2^{2}+3^{2}+\ldots+10^{2}=385$, then find the value of $2^{2}+4^{2}+6^{2}+\ldots+20^{2}$.
Answer
Answer (as printed):
Explanation
$2^{2}+4^{2}+6^{2}+\ldots+20^{2}=2^{2}(1^{2}+2^{2}+3^{2}+\ldots+10^{2})=2^{2}\times 385=4\times 385=1540$.

Explanation as extracted from the printed page; notation may be imperfect.

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