Given that 1²+2²+3²+…+10²=385, then find the value of 2²+4²+6²+…+20². · ABC26GN0015

Subject: General Aptitude · Chapter: Number System

Given that $1^{2}+2^{2}+3^{2}+\ldots+10^{2}=385$, then find the value of $2^{2}+4^{2}+6^{2}+\ldots+20^{2}$.

Answer

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Explanation

$2^{2}+4^{2}+6^{2}+\ldots+20^{2}=2^{2}(1^{2}+2^{2}+3^{2}+\ldots+10^{2})=2^{2}\times 385=4\times 385=1540$.

Explanation as extracted from the printed page; notation may be imperfect.

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