ABC26GN0028 · Number System

Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:

Find the number which is nearest to 3105 and is exactly divisible by 21.
Answer
Answer (as printed):
Explanation
On dividing 3105 by 21, we get 18 as remainder. \ Number to be added to 3105 = (21 – 18) = 3. Hence, required number = 3105 + 3 = 3108.

Explanation as extracted from the printed page; notation may be imperfect.

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