The prime numbers dividing 143 and leaving a remainder of 3 in each case are · ABC26GN0115

Subject: General Aptitude · Chapter: Number System

The prime numbers dividing 143 and leaving a remainder of 3 in each case are

(a)2 and 11

(b)11 and 13

(c)3 and 7

(d)5 and 7

Answer

Answer (as printed): D

Explanation

Each of the required numbers must divide $(143-3)=140$ exactly. Now, $140=5 \times 7 \times 4$. Hence, the required prime numbers are 5 and 7.

Explanation as extracted from the printed page; notation may be imperfect.

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