The number of zeros at the end of 60 ! is · ABC26GN0232
Subject: General Aptitude · Chapter: Number System
The number of zeros at the end of 60 ! is
(a)12
(b)14
(c)16
(d)18
Answer
Answer (as printed): B
Explanation
Clearly, highest power of 2 is much higher as compared to that of 5 in 60!, so Required number of zeros = Highest power of $$5=\left[\frac{60}{5}\right]+\left[\frac{60}{5^{2}}\right]=12+2=14 .$$
Explanation as extracted from the printed page; notation may be imperfect.