Subject: General Aptitude · Chapter: Number System · Exam: 2010 · Marks: · Difficulty:
Let $x$ be the product of two numbers 3,659,893,456,789,325,678 and 342,973,489,379,256. The number of digits in $x$ is
(a)32
(b)34
(c)35
(d)36
Answer
Answer (as printed): B
Explanation
Sum of digits in the two numbers $=19+15=34$. So, the product will have 33 or 34 digits. Since $36 \times 34=1224$ (i.e. product has $2+2=4$ digits), so the number of digits in $x$ is 34.
Explanation as extracted from the printed page; notation may be imperfect.