Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:
If the number 357*25* is divisible by both 3 and 5, then the missing digits in the unit's place and the thousandth's place respectively are
(a)0, 6
(b)5, 1
(c)5, 4
(d)None of these
Answer
Answer (as printed): D
Explanation
Let the unit's place be x and the thousand's place be y. Then, 357y25x is divisible by 5 only when x = 0 or x = 5. Also, this number is divisible by 3 only when sum of its digits is divisible by 3. So, (22 + x + y) must be divisible by 3. \x+y=2 Taking x = 0, we get y = 2. So, the unit place = 0 and thousand's place = 2.
Explanation as extracted from the printed page; notation may be imperfect.